Mathematics MCQ | Class 09 | Chapter 14
STATISTICS

Features

Action Plan

MCQ |Chapter 14 | Statistics | Class IX

Question: 1

The collection of information, collected for a purpose is called:

a) Mean

b) Median

c) Mode

d) Data

Answer: d

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       Mathematics MCQ | Class 09 | Chapter 15

PROBABILITY

Features

Action Plan

MCQ |Chapter 15 | Probability | Class IX

Question 1

1) The probability of
each event, when a coin is tossed for 1000 times with frequencies: Head: 455
& Tail: 545 is:

a)
0.455 & 0.545

b)
0.5 & 0.5

c)
0.45 & 0.55

d)
455 & 545

Answer: a

Question 2

Marks
obtained by a student in a test is shown in the table below.

Test no.	1	2	3	4	5
Marks	81	87	76	70	90

What is the probability that the student has scored more than
80?
a) 3/5
b) 4/5
c) 2/5
d) 1/2

Answer a

Question 3

When a die is thrown, what is
the probability of getting even number

a) 1/6

b) 1/3

c) 1/2

d) 2/3

Answer c

Question 4

The sum of all probabilities equal to:

a)
4

b)
1

c)
3

d)
2

Answer: b

Question 5

3) The probability of each
event lies between:

a)
1 & 2

b)
1 & 10

c)
0 & 1

d)
0 & 5

Answer: c

Question 6

Probability
of impossible event is 

a)
1

b)
0

c) Less
than 0

d)
Greater than 1

Answer
b

Question 7

If P(E) = 0.44, then P(not
E) will be:

a)
0.44

b)
0.55

c)
0.50

d)
0.56

Answer: d

Explanation: We know;

P(E) + P(not E) = 1

0.44 + P(not E) = 1

P(not E) = 1 – 0.44 = 0.56

Question 8

Probability
of certain (sure) event is

a) 1

b) 0

c)
Greater than 1

d)
Less than 0

Answer
a

Question 9

 If P(E) = 0.38, then
probability of event E, not occurring is:

a)
0.62

b)
0.38

c)
0.48

d)
1

Answer: a

Explanation: P(not E) = 1 – P(E) = 1-0.38 = 0.62

Question 10

Two coins are tossed simultaneously.
The probability of getting atmost one head is

a) 1/4

b) 3/4

c) 1/2

d) 1/4

Answer b

Question 11

The probability of drawing
an ace card from a deck of cards is:

a)
1/52

b)
1/26

c)
4/13

d)
1/13

Answer: d

Explanation: There are 4 aces in a deck of card.

Hence, the probability of taking one ace out of 52 cards = 4/52
= 1/13

Question 12

A coin is tossed 1000 times,
if the probability of getting a tail is 3/8, how many times head is obtained.

a) 525

b) 375

c) 625

d) 725

Answer b

Question 13

If the probability of an
event to happen is 0.3 and the probability of the event not happening is:

a)
0.7

b)
0.6

c)
0.5

d)
None of the above

Answer: a

Explanation: Probability of an event not happening = 1 – P(E)

P(not E) = 1 – 0.3 = 0.7

Question 14

A coin is tossed 1000 times,
if the probability of getting a tail is 3/8, how many times head is obtained.

a) 525

b) 375

c) 625

d) 725

Answer c

Question 15

 A dice is thrown. The
probability of getting 1 and 5 is:

a)
1/6

b)
2/3

c)
1/3

d)
1/2

Answer: c

Explanation: The probability of getting 1 and 5 = 2/6 = 1/3

Question 16

In a football match, Ronaldo
makes 4 goals from 10 panalty kicks. The probability of converting a penalty
kick into a goal by Ronaldo, is

a) 1/4

b) 1/6

c) 1/3

d) 2/5

Answer d

Question 17

A batsman hits boundaries
for 6 times out of 30 balls. Find the probability that he did not hit the boundaries.

a)
1/5

b)
2/5

c)
3/5

d)
4/5

Answer: d

Explanation: No. of boundaries = 6

No. of balls = 30

No. of balls without boundaries = 30 – 6 =24

Probability of no boundary = 24/30 = 4/5

Question 18

From a deck of 52 shuffled playing
cards, a card is drawn What is the probability of drawing a king or queen

a) 1/13

b) 2/13

c) 3/13

d 1/52

Answer b

Question 19

Three coins were tossed
200 times. The number of times 2 heads came up is 72. Then the probability of 2
heads coming up is:

a)
1/25

b)
2/25

c)
7/25

d)
9/25

Answer: d

Explanation: Probability = 72/200 = 9/25

Question 20

From a deck of 52 shuffled playing
cards, a card is drawn What is the probability of drawing a red face card

a) 1/13

b) 2/13

c) 3/26

d 1/26

Answer c

Question 21

What is the probability of getting an odd number less than 4, if a die is
thrown?

a) 1/6

b) 1/2

c) 1/3

d) 0

Answer: c

Explanation:
Sample space, S = {1, 2, 3, 4, 5, 6}

Favorable
outcomes = {1, 3}

Therefore, the
probability of getting an odd number less than 4 = 2/6 = 1/3.

Question 22

From a deck of 52 shuffled playing
cards, a card is drawn What is the probability of drawing a black king card

a) 1/13

b) 2/13

c) 3/26

d 1/26

Answer d

Question 23

What is the probability of impossible events?

a) 1

b) 0

c) More than 1

d) Less than 1

Answer: b

Explanation: The
probability of an impossible event is always 0.

Question 24

 Performing an event once is called

a) Sample

b) Trial

c) Error

d) None of the above

Answer: b

Explanation:
Performing an event once is called a trial.

Question 25

In a counting from 1 to 10,
what is the probability of finding a prime number

a) 1/2

b)  3/10

c) 2/5

d) 1/10

Answer c

Question 26

 A card is drawn from a well-shuffled deck of 52 cards. What is the probability
of getting a king of the red suits?

a) 3/36

b) 1/26

c) 3/26

d) 1/16

Answer: b

Explanation: In
a pack of 52 cards, there are a total of 4 king cards, out of which 2 are red
and 2 are black.

Therefore, in a
red suit, there are 2 king cards. 

Hence, the
probability of getting a king of red suits = 2/52 = 1/26.

Question 27

In a counting from 1 to 10,
what is the probability of finding a composite number

a) 1/2

b)  3/10

c) 2/5

d) 1/10

Answer a

Question 28

 Find the probability of a selected number is a multiple of 4 from the numbers
1, 2, 3, 4, 5, …15.

a) 1/5

b) 1/3

c) 4/12

d) 2/15

Answer: a

Explanation: S =
{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}

Multiples of 4
from the sample space = {4, 8, 12}

Therefore, the
probability of the selected number is a multiple of 5 is 3/15 = 1/5.

Question 29

In the word MATHEMATICS, what
is the probability of finding a vowel

a) 1/11

b) 2/11

c) 3/11

d) 4/11

Answer d

Question 30 

What is the probability of drawing a queen from the deck of 52 cards?

a) 1/26

b) 1/52

c) 1/13

d) 3/52

Answer: c

Explanation:
Total cards = 52

Number of queens
in a pack of 52 cards = 4

Hence, the
probability of drawing a queen from a deck of 52 cards = 4/52 = 1/13

Question 31

In the word MATHEMATICS, what
is the probability of finding a consonant

a) 5/11

b) 6/11

c) 4/11

d) 7/11

Answer d

Question 32

Which of the following cannot be the probability of an event?

a) 1

b) 0

c) 0.75

d) 1.3

Answer: d

Explanation: The
probability of an event always lies between 0 and 1.

Question 33

There are 4 green and 2 red balls in a basket. What is the probability of
getting the red balls? 

a) 1/2

b) 1/3

c) 1/5

d) 1/6

Answer: b

Explanation:
Total balls = 4 green + 2 red = 6 balls

No. of red balls
= 2.

Hence, the
probability of getting the red balls = 2/6 = 1/3

Question 34

Empirical probability is also known as 

a) Classic probability

b) Subjective probability

c) Experimental probability

d) None of the above

Answer: c

Explanation: Empirical
probability is also known as experimental probability.

Question 35

If two coins are tossed simultaneously, then what is the probability of getting
exactly two tails?

a) 1/4

b) 1/2

c) 1/3

d) None of the above

Answer: a

Explanation: If
two coins are tossed, then the sample space, S = {HH, HT, TH, TT}

Favorable
outcome (Getting exactly two tails) = {TT} 

Therefore, the
probability of getting exactly two heads = 1/4

 

      Mathematics MCQ | Class 09 | Chapter 10

CIRCLE

Features

Action Plan

MCQ |Chapter 10 | Circle | Class IX

Question 1

The collection of all the points in a plane, which are at a fixed distance from a fixed point in the plane, is called
a) square
b) triangle
c) rectangle
d) circle

Answer d

Question 2

The centre of the circle lies in______ of the circle.
a) Interior
b) Exterior
c) Circumference
d) None of the above
Answer: a

Question 3

A circle divides the plane into __________ parts.
a) two
b) three
c) four
d) five
Answer b

Question 4

The longest chord of the circle is:
a) Radius
b) Arc
c) Diameter
d) Segment
Answer: c

Question 5

From the diagram given below, the shaded area is __________

a) major segment
b) minor segment
c) major sector
d) minor segment
Answer b

Question 6

How many circles can pass through three points which are not collinear?
a) One
b) Two
c) Three
d) Four
Answer a

Question 7

Equal _____ of the congruent circles subtend equal angles at the centres.

a) Segments
b) Radii
c) Arcs
d) Chords
Answer: d
Explanation: See the figure below:

Let ΔAOB and ΔCOD are two triangles inside the circle.

OA = OC and OB = OD (radii of the circle)

AB = CD (Given)

So, ΔAOB ≅ ΔCOD (SSS congruency)

∴  ∠AOB = ∠COD ……….. By CPCT

Hence, this prove the statement.

Question 8

The region between an arc and the two radii, joining the centre to the end points of the arc is called __________
a) arc
b) chord
c) sector
d) area of circle
Answer c

Question 9

When does both segments and both sectors become equal?
a) When two arcs are equal
b) When radius = 2 x chord
c) When two arcs are unequal
d) When chord = radius
Answer a

Question 10

If chords AB and CD of congruent circles subtend equal angles at their centres, then:
a) AB = CD
b) AB > CD
c) AB < AD
d) None of the above
Answer: a
Explanation:
In triangles AOB and COD,
∠AOB = ∠COD (given)
OA = OC and OB = OD (radii of the circle)
So, ΔAOB ≅ ΔCOD. (SAS congruency)
∴ AB = CD (By CPCT)

Question 11
From the diagram given below, if O is the centre of the circle and OL is perpendicular to chord AB, then which of the following is true?

a) AL > LB
b) AL < LB
c) AL ≠ LB
d) AL = LB
Answer d

Question 12

If there are two separate circles drawn apart from each other, then the maximum number of common points they have:
a) 0
b) 1
c) 2
d) 3
Answer: a

Question 13

What is the value of AC if radius of circle is 5cm and OB = 3cm?

a) 5cm

b) 8cm
c) 4cm
d) 2cm

Question 14

The
angle subtended by the diameter of a semi-circle is:

a) 90^o
b) 45^o
c) 180^o
d) 60^o
Answer: c

Explanation: Angle in a semi circle is always right

Question 15

Find the value of AB if radius of circle is 10cm and PQ = 12cm and RS = 16cm?

a) 14cm
b) 16cm
c) 4cm
d) 2cm
Answer d

Question 16
If AB and CD are two chords of a circle intersecting at point E, as per the given figure. Then:

a) ∠BEQ > ∠CEQ
b) ∠BEQ = ∠CEQ
c) ∠BEQ < ∠CEQ
d) None of the above
Answer: b

Explanation:

OM = ON …………….. (Equal chords are always equidistant from the centre)

OE = OE  …………….. (Common)

∠OME = ∠ONE …… (Each = 90^o)

So, ΔOEM ≅ ΔOEN ……… (by RHS congruence rule)

Hence, ∠MEO = ∠NEO …….. (by CPCT)

∴ ∠BEQ = ∠CEQ

Question 17

Find the radius of circle if AB = 7cm, RS = 6cm and PQ = 8cm.

a) 5cm

b) 8cm
c) 4cm
d) 20cm
Answer a

Explanation:

Let r be the radius of circle.
Since perpendicular from centre to a chord bisects the chord,
AR = RS/2 = 3cm and BP = PQ/2 = 4cm
In ΔBOP, ∠OBP = 90°
By Pythagoras theorem, OP² = OB² + BP²
⇒ r² = x² + (4)²
⇒ r² = x² + 16  ——————- (i)
Similarly, In ΔAOR, ∠OAR = 90°
By Pythagoras theorem, OR² = OA² + AR²
⇒ r² = (7 – x)² + (3)²
⇒ r² = (7 – x)² + 9  ———————— (ii)
From equation i and ii, x² + 16 = (7 – x)² + 9
⇒ x² + 16 = 7² – 2 x 7 x x + x² + 9
⇒ 2 x 7 x x = 49 – 16 + 9
⇒ x = 3
Substituting value of x in equation i, r² = 3² + 16
⇒ r = 5cm.

Question 18
If a line intersects two concentric circles with centre O at A, B, C and D, then:
a) AB = CD
b) AB > CD
c) AB < CD
d) None of the above
Answer: a
Explanation: See the figure below:

From the above fig., OM ⊥ AD.

Therefore, AM = MD …….. (1)

Also, since OM ⊥ BC, OM bisects BC.

Therefore, BM = MC ……… (2)

From equation (1) and equation (2)

AM – BM = MD – MC

∴ AB = CD

Question 19
Two circles of radius 13cm and 17cm intersect at A and B. What is the distance between the centres of the circles if AB = 24cm?

a) 15cm
b) 25cm
c) 22cm
d) 14cm
Answer d

Explanation:
Since line joining the centres of the circles bisects the common chord, AC = BC = 12cm.
Also, In ΔAOC, ∠OCA = 90°
By Pythagoras theorem, OA² = OC² + AC²
⇒ 15² = OC² + 12²
⇒ OC² = 225 – 144
⇒ OC = 9cm
Similarly, In ΔAO’C, ∠O’CA = 90°
By Pythagoras theorem, O’A² = O’C² + AC²
⇒ 13² = O’C² + 12²
⇒ OC² = 169 – 144
⇒ OC = 5cm
Now, OO’ = OC + O’C
⇒ OO’ = 9 + 5 = 14cm.

Question 20

In the below figure, the value of ∠ADC is:

a) 60°
b) 30°
c) 45°
d) 55°
Answer: c

Explanation: ∠AOC = ∠AOB + ∠BOC

So, ∠AOC = 60° + 30°

∴ ∠AOC = 90°

An angle subtended by an arc at the centre of the circle is twice the angle subtended by that arc at any point on the rest part of the circle.

So, ∠ADC = 1/2∠AOC

= 1/2 × 90° = 45°

Question 21
In the given figure, find angle OPR.

a) 20°
b) 15°
c) 12°
d) 10°
Answer: d

Explanation: Major arc PR subtend Reflex ∠POR at the centre of the circle and ∠PQR in the remaining part of the circle

So, Reflex ∠POR = 2 × ∠PQR,

We know the values of angle PQR as 100°

So, Reflex ∠POR = 2 × 100° = 200°

∴ ∠POR = 360° – 200° = 160° 

Now, in ΔOPR,

OP and OR are the radii of the circle

So, OP = OR

Also, ∠OPR = ∠ORP = x

By angle sum property of triangle, we know:

∠POR + ∠OPR + ∠ORP = 180°

160° + x + x  = 180°

2x = 180° – 160°

2x = 20° ⇒ x = 10°

Question 22

In the given figure, ∠AOB = 90º and ∠ABC = 30º, then ∠CAO is equal to:

a) 30º
b) 45º
c) 60º
d) 90º
Answer: c
Explanation:

Given that ∠AOB = 90º and ∠ABC = 30º
OA = OB (Radii of the circle)
Let ∠OAB = ∠OBA = x
In the triangle OAB,
∠OAB + ∠OBA + ∠AOB = 180° (By using the angle sum property of triangle)
⇒ x + x + 90° = 180°
⇒ 2x = 180° – 90°
⇒ x = 90°/ 2 = 45°
Therefore, ∠OAB = 45° and ∠OBA = 45°
By using the theorem, “ the angles subtended by arcs at the centre of the circle double the angle subtended at the remaining part of the circle”, we can write
∠AOB = 2∠ACB
This can also be written as,
∠ACB = ½ ∠AOB = (½) × 90° = 45°
Now, apply the angle sum property of triangle on the triangle ABC,
∠ACB + ∠BAC + ∠CBA = 180°
45° + 30° + ∠BAC = 180°
75° + ∠BAC = 180° ⇒ ∠BAC = 180° – 75°
⇒ ∠BAC = 105°
∠CAO + ∠OAB = 105°
∠CAO + 45° = 105°
⇒ ∠CAO = 105° – 45° = 60°
Question 23

ABCD is a cyclic quadrilateral such that AB is a diameter of the circle circumscribing it and ∠ADC = 140º, then ∠BAC is equal to:

a) 30º
b) 40º
c) 50º
d) 80º
Answer: c

Explanation:

Given that ABCD is a cyclic quadrilateral and ∠ADC = 140º.

We know that the sum of opposite angles of a cyclic quadrilateral is 180°.

Hence, ∠ADC + ∠ABC = 180° 

140° + ∠ABC = 180°

∠ABC = 180° – 140° = 40° 

Now  ∠ACB = 90° . . . . . . .  Angles in the semi circle is right

By using the angle sum property of triangle in the triangle, ABC, 

∠CAB + ∠ABC + ∠ACB = 180°

∠CAB + 40° + 90° = 180° 

∠CAB + 130°   = 180° 

∠CAB = 180° – 130°

∠CAB = 50° 

Therefore, ∠CAB or ∠BAC =50°.

Question 24

 In the given figure, if ∠OAB = 40º, then ∠ACB is equal to

a) 40º
b) 50º
c) 60º
d) 70º
Answer: b
Explanation:

Given that ∠OAB = 40º,

In  the triangle OAB, 

OA = OB (radii)

 ∠OAB = ∠OBA  = 40°  …… (∴ angles opposite to equal sides are equal)

Now, by using the angle sum property of triangle, we can write

∠AOB + ∠OBA + ∠BAO = 180° 

∠AOB + 40° + 40° = 180° 

∠AOB = 180 – 80° = 100° 

Since, the angle subtended by an arc at the centre is twice the angle subtended by it at the remaining part of the circle

∠AOB = 2 ∠ACB 

∠ACB = ½ ∠AOB

Hence, ∠ACB = 100°/2 = 50°.

Question 25

In the given figure, if ∠ABC = 20º, then ∠AOC is equal to:

a) 10º
b) 20º
c) 40º
d) 60º
Answer: c
Explanation:
Given that, ∠ABC = 20º.
since the angle subtended by an arc at the centre of the circle is double the angle subtended at the remaining part.
∠AOC = 2∠ABC
∠AOC = 2 × 20° = 40°.

     Mathematics MCQ | Class 09 | Chapter 13

SURFACE AREA & VOLUME

Features

Action Plan

MCQ BASED ON CUBE AND CUBOID

Q1) The formula to
find the surface area of a cuboid of length (l), breadth (b) and height (h) is:

a)
lb + bh + hl

b)
2(lb + bh + hl)

c)
2(lbh)

d)
lbh/2

Answer: b

Q2) If the perimeter of one of the faces of a cube is 40 cm, then its
volume is:

a) 6000 cm³

b) 1600 cm³

c) 1000 cm³

d) 600 cm³

Answer: c

Q3) The surface area
of a cube whose edge equals to 3cm is:

a)
62 sq.cm

b)
30 sq.cm

c)
54 sq.cm

d)
90 sq.cm

Answer: c

Explanation: Given, a = 3 cm

Surface area of cube = 6a²

SA = 6 x 3 x 3 = 54 sq.cm

Q4) The
surface area of a cube whose edge equals to 3cm is:

a) 62 sq.cm

b) 30 sq.cm

c) 54 sq.cm

d) 90 sq.cm

Answer c

Q5) The surface area of
cuboid-shaped box having length = 80 cm, breadth = 40cm and height = 20cm is:

a)
11200 sq.cm

b)
13000 sq.cm

c)
13400 sq.cm

d)
12000 sq.cm

Answer: a

Explanation: surface area of the box = 2(lb + bh + hl)

S.A. = 2[(80 × 40) + (40 × 20) + (20 × 80)]

= 2[3200 + 800 + 1600]

= 2 × 5600 = 11200 sq.cm.

Q6) The
length of the longest pole that can be put in a room of dimension (10 m × 10 m
× 5 m) is

a) 15 m

b) 16 m

c) 10 m

d) 12 m

Answer: a

Q7) The total surface
area of a cube is 96 cm². The volume
of the cube is:

a) 8 cm³ 

b) 512 cm³

c) 64 cm³

d) 27 cm³

Answer: c

Explanation:

We know
that the TSA of the cone = 6a².

6a² = 96 cm²

a² = 96/6 = 16

a = 4 cm

The volume
of cone = a³ cubic units

V = 4³ = 64cm³.

Q8) The
lateral surface area of a cube is 256 m³. The volume of the cube is

a) 512 m³

b) 64 m³

c) 216 m³

d) 256 m³

Answer: a

Q9)
The length of the longest pole that can be put in a room of dimensions (10 m ×
10 m × 5m) is

a) 15m

b) 16m

c) 10m

d) 12m

Answer: a

Explanation:

Given: l = 10m,
b = 10m, h = 5m

The length
of the longest pole = √[10² +
10² + 5²]

= √(100 + 100
+ 25) = √225 = 15 m.

Q10)
The number of planks of dimensions (4 m × 50 cm × 20 cm) that can be stored in
a pit that is 16 m long, 12m wide and 4 m deep is

a) 1900

b) 1920

c) 1800

d) 1840

Answer: b

Explanation:

Volume of
Plank = 400 cm × 50cm × 20cm = 400000cm³

Volume of
pits = 1600cm × 1200cm × 400cm = 768000000cm³

Number of
planks = Volume of planks/Volume of pits

=
768000000/400000

Hence, the
number of pits = 1920

Q11) The
total surface area of a cube is 96 cm². The volume of the cube is

a) 8 cm³

b) 512 cm³

c) 64 cm³

d) 27 cm³

Answer: c

Q12)
The lateral surface area of a cube is 256 m².
The volume of the cube is

a) 512 m³

b) 64 m³

c) 216 m³

d) 256 m³

Answer: a

Explanation:

The lateral
surface area of cube = 4a²

4a² = 256

a² = 256/4 =64

a = 8 m

Hence, the
volume of cube = a³ cube
units 

V = 8³  = 512 m³.

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    Mathematics

MCQ | Class 09 | Chapter 7
Triangles

Features

Action Plan

MCQ | CHAPTER – 7 | CLASS IX
TRIANGLES

Question 1

In triangle ABC, if AB = BC and ∠B = 70°, ∠A will be:

a) 70°                    b) 110°                c) 55°                    d) 130°

Answer: c

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   Mathematics

MCQ | Class 09 | Chapter 8
Quadrilaterals

Features

Action Plan

MCQ | CHAPTER – 8 | CLASS IX
QUADRILATERAL

Q1) The quadrilateral whose all its sides
are equal and angles are equal to 90 degrees, it is called:

a) Rectangle

b) Square

c) Kite

d) Parallelogram

Answer: b

Q2) Quadrilateral has __________ sides.
a) one
b) two
c) three
d) four

Answer:  d

Q3) The sum of all the angles of a quadrilateral
is equal to:

a) 180°

b) 270°

c) 360°

d) 90°

Answer: c

Q4) The sum of four angles of quadrilateral is equal
to _______
a) 90°
b) 360°
c) 180°
d) 270°

Answer:  b

Q5) A trapezium has:

a) One pair of opposite sides parallel

b) Two pairs of opposite sides parallel to each other

c) All its sides are equal

d) All angles are equal

Answer: a

Q6) Find the value of x.

a) 105°
b) 50°
c) 60°
d) 90°

Answer:  a

Q7) A
rhombus can be a:

a) Parallelogram

b) Trapezium

c) Kite

d) Square

Answer: d

Q8) At which angle do diagonals of a rhombus bisects
each other?
a) 180°
b) 360°
c) 270°
d) 90°

Answer:  d

Q9) A diagonal of a parallelogram divides it
into two congruent:

a) Square

b) Parallelogram

c) Triangles

d) Rectangle

Answer: c

Q10) What is the quadrilateral formed by the angle
bisectors of a parallelogram?
a) Square
b)
Rectangle
c) Circle
d) Rhombus

Answer:  b

Q11) In a parallelogram, opposite angles are:

a) Equal

b) Unequal

c) Cannot be determined

d) None of the above

Answer: a

Q12) Find the value of x if PQRS is a parallelogram.

a) 150°
b) 50°
c) 60°
d) 120°

Answer:  c

Q13) The diagonals of a parallelogram are

a) Equal

b) Unequal

c) Bisect each other

d) Have no relation

Answer: c

Q14) From the figure find
the length of AD if perimeter of parallelogram ABCD is 26cm.

a) 10 cm
b) 15 cm
c) 12 cm
d) 5 cm

Answer:  d

Q15) Each angle of the rectangle is:

a) More than 90°

b) Less than 90°

c) Equal to 90°

d) Equal to 45°

Answer: c

Q16) The angles of a quadrilateral are in
the ratio 4 : 5 : 10 : 11. The angles are:

a) 36°, 60°, 108°, 156°

b) 48°, 60°, 120°, 132°

c) 52°, 60°, 122°, 126°

d) 60°, 60°, 120°, 120°

Answer: b

Explanation:

As per
angle sum property, we know:

4x+5x+10x+11x = 360°

30x = 360°

x = 12°

Hence, angles are

4x = 4 (12) = 48°

5x = 5 (12) = 60°

10x = 10 (12) = 120°

11x = 11 (12) = 132°

Q17) If ABCD is a trapezium in which AB || CD
and AD = BC, then:

a) ∠A = ∠B

b) ∠A > ∠B

c) ∠A < ∠B

d) None of the above

Answer: a

Explanation : See Q12 Exercise 8.1 NCERT

Q18)
Which of the following is not true for a parallelogram?

a) Opposite
sides are equal

b) Opposite
angles are equal

c) Opposite
angles are bisected by the diagonals

d)
Diagonals bisect each other.

Answer: c

Q19) If the ratio of four angles of a quadrilateral is ∠A : ∠B : ∠C : ∠D = 1 : 2 : 3 : 4, what
is the value of ∠C?
a) 90°
b) 108°
c) 180°
d) 72°

Answer:  b

Q20) Three angles of a quadrilateral are 75º,
90º and 75º. The fourth angle is

a) 90º

b) 95º

c) 105º

d) 120º

Answer: d

Explanation:
We know that the sum of angles of a quadrilateral is 360º.

Let the
unknown angle be x.

Therefore,
75º + 90º + 75º + x = 360º

x = 360º –
240º = 120º.

Q21) What is the length of
DE if DE || BC and D and E are midpoints of AB and AC?

a) 18cm
b) 15cm
c) 9cm
d) 20cm

Answer:  c  (9 cm)

Q22) ABCD is a rhombus such that ∠ACB = 40º. Then ∠ADB is

(a) 40º

(b) 45º

(c) 50º

(d) 60º

Answer: c

Explanation:
We know that the diagonals of the rhombus bisect each other perpendicularly.

By using
the alternate interior angles, and angle sum property of triangle, we can say:

From the
triangle, BOC,

∠BOC + ∠OCB + ∠OBC = 180º

(where 
∠BOC= 90º, ∠OCB = 40º)

90º + 40º + ∠OBC = 180º

∠OBC = 180º – 130º

∠OBC = 50º

∠OBC =∠DBC

Now, by
using alternate angles, we can say

∠ADB = 50º

Q23)  Find the perimeter of
ΔABC, if perimeter of ΔPQR is 36cm and A, B and C are midpoints.

a) 9cm
b) 18cm
c) 20cm
d) 36cm

Answer:  b

Q24) The quadrilateral formed by joining the mid-points
of the sides of a quadrilateral PQRS, taken in order, is a rhombus, if

a) PQRS is
a rhombus

b) PQRS is
a parallelogram

c)
Diagonals of PQRS are perpendicular

d)
Diagonals of PQRS are equal.

Answer: d

Explanation:
The quadrilateral formed by joining the mid-points of the sides of a
quadrilateral PQRS, taken in order, is a rhombus if the diagonals of PQRS are
equal.

Q25) A diagonal of a
parallelogram divides it into two congruent:

a. Square

b. Parallelogram

c. Triangles

d. Rectangle

Answer c

Q26) A diagonal of a rectangle is inclined to
one side of the rectangle at 25º. The acute angle between the diagonals is

a) 25º

b) 40º

c) 50º

d) 55º

Answer: c

Explanation:
Consider the rectangle ABCD

In a
triangle BOC, 

∠OBC = ∠OCB (Opposite angles of isosceles triangle)

Therefore, ∠OBC + ∠OCB + ∠BOC = 180º

25º + 25º + ∠BOC = 180º

∠BOC = 180º- 50º

∠BOC = 130º.

By using
the linear pair, 

∠AOB + ∠BOC = 180º

∠AOB = 180º – 130º

∠AOB= 50º

Hence, the
acute angle between the diagonals is 50º.

Q27) In a parallelogram,
opposite angles are:

a. Equal

b. Unequal

c. Cannot be determined

d. None of the above

Answer a

Q28) If angles A, B, C and D of the quadrilateral
ABCD, taken in order, are in the ratio 3 : 7 : 6 : 4, then ABCD is a

a) Kite

b) Rhombus

c)
Parallelogram

d) Trapezium

Answer: d

Explanation: Given that,
the angles A, B, C and D of a quadrilateral are in the ratio 3 : 7 : 6 : 4.

We know
that A + B + C + D = 360º

Hence, now
we can assume, 3x + 7x + 6x + 4x = 360º

20x = 360º

x=18º

Therefore,
A = 3x = 54º

B = 7x =
126º

C = 6x =
108º

D = 4x= 72º

Here ∠A + ∠B = 180^o

 ⇒ AD ॥ BC

And ∠C + ∠D = 180^o

 ⇒ AD ॥ BC

⇒ ABCD is a quadrilateral with
one pair of opposite sides are parallel.

⇒ ABCD is a trapezium

Q29) The quadrilateral formed by joining
the mid-points of the sides of a quadrilateral PQRS, taken in order, is a
rectangle, if

a) PQRS is
a rectangle

b) PQRS is
a parallelogram

c)
Diagonals of PQRS are perpendicular

d)
Diagonals of PQRS are equal

Answer: c

Explanation:
The quadrilateral formed by joining the mid-points of the sides of a
quadrilateral PQRS, taken in order, is a rectangle, if the diagonals of PQRS
are perpendicular.

Q30) Each angle of rectangle
is:

a. More than 90°

b. Less than 90°

c. Equal to 90°

d. Equal to 45°

Answer c

Q31) The figure obtained by joining the
mid-points of the sides of a rhombus, taken in order, is

a) a square

b) a rhombus

c) a
rectangle

d) any
parallelogram

Answer: c

Explanation:
See Q2 NCERT Ex- 8.2

Let ABCD be
a rhombus. P, Q, R, S be the midpoint of the sides AB, BC, CD and DA. If we
join the midpoints, we will get the shape rectangle.

Q32) If APB and CQD are two parallel lines, then
the bisectors of the angles APQ, BPQ, CQP and PQD form

a) Square

b) Rectangle

c) Rhombus

d) any
other parallelogram

Answer: b

Explanation: Hence, the
bisectors of the angles APQ, BPQ, CQP and PQD form the shape rectangle.

Q33) Which of the following is not a
quadrilateral?

a) Kite

b) Square

c) Triangle

d) Rhombus

Answer: c

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  Mathematics

MCQ | Class 09 | Chapter 6
Lines and Angles

Features

Action Plan

MCQ | CHAPTER – 6 | CLASS IX
LINES AND ANGLES

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MCQ | Class 09 | Chapter 4
Linear Equations in Two Variables

Features

Action Plan

MCQ | CHAPTER – 4 | CLASS IX
LINEAR EQUATIONS IN TWO VARIABLES

Q1)  The linear equation
3x – 11y = 10 has:

a. Unique solution

b. Two solutions

c. Infinitely many solutions

d. No solutions

Answer: c

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MCQ | Class 09 | Chapter 2
Polynomials

Features

Action Plan

MCQ | CHAPTER – 2 | CLASS IX
POLYNOMIALS

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  Mathematics

MCQ | Class 09 | Chapter 1
Real Numbers

Features

Action Plan

MCQ | CHAPTER – 1 | CLASS IX
REAL NUMBERS

Q1) Can we write 0 in the form of p/q?

a. Yes

b. No

c. Cannot be
explained

d. None of the
above

Answer:
a