Mathematics
Multiple Choice Questions (MCQ)
MCQ | Class 10 | Chapter 15
PROBABILITY
- MCQ Based on the tossing of one coin, two coins and three coins.
- MCQ Based on the Tossing of one die and two die.
- MCQ Based on the Playing cards
- MCQ Based on the general problems of probability.
- MCQ Based from the CBSE Sample Questions
Features
- In this pdf given below you find the important MCQ which are strictly according to the CBSE syllabus and are very useful for the CBSE Examinations.
- Solution Hints are also given to some difficult problems.
- Each MCQ contains four options from which one option is correct.
Action Plan
- First of all students should Learn and write all basic points and Formulas related to the Probability.
- Start solving the NCERT Problems with examples.
- Solve the important assignments on the Probability.
- Then start solving the following MCQ.
MCQ | CHAPTER 15 | CLASS 10
PROBABILITY
Q 1) The probability of event equal to zero is called;
(a) Certain event
(b) Sure Event
(c) Impossible event
(d) Independent event
Q 2) What is the probability of a sure event?
a) 0
b) 1
c) 2
d) 3
Q 3) The probability that cannot exist among the following:
(a) 2 / 3
(b) -1.5
(c) 15%
(d) 0.7
a) 1/ 34
b) 1/ 4
c) 12/ 13
d) 3/ 4
(a) 0.93
(b) 0.95
(c) 0.89
(d) 0.90
Ans: a
Explanation:
Since, P(E) = 0.05
(a) 1024
(b) 512
(d) 10
Ans: a Explanation :
(a) 3
(b) 8
(c) 3/8
(d) 8/3
(a) 0.5
(b) 0.66
(c) 0.08
(d) 0.77
(a) 1/2
(b) 3/2
(c) 3
(d) 4
a) 1
b) 1/ 2
c) 1/ 4
d) 1/ 8
Ans: d
∴ P(all heads) =1/8
(a) 2/18
(b) 3/18
(c) 1/18
(d) 1/36
Ans: c
Explanation: When two dice are thrown in the air:
Total number of outcome = 6 x 6 = 36
Sum 3 is possible if we get (1,2) or (2,1) in the dices.
(a) 1/26
(b) 1/13
(c) 4/53
(d) 4/13
b) 1/ 13
c) 1/ 4
d) 1/ 2
Ans: a
Total events (S) = 52
a king of red color = 2
P(a king of red color) = 2/52 = 1/26
(a) 0.5
(b) 1
(c) 2
(d) 1.5
(a) 3/13
(b) 4/13
(c) 6/13
(d) 9/13
a) 3/ 13
b) 10/ 13
c) 7/ 13
d) 4/ 13
Ans: b
Total face cards = 12
∴ Non-face cards = 52 – 12 = 40
∴ P(a non-face card)= 40/52 = 10/13
(a) 1
(b) 3/4
(c) 1/2
(d) 0
(a) P(A) < 0
(b) P(A) > 1
(c) 0 ≤ P(A) ≤ 1
(d) –1 ≤ P(A) ≤ 1
(a) 4
(b) 13
(c) 48
(d) 51
Ans: d
Explanation
In a deck of 52 cards, there are 13 cards of heart and 1 is ace of heart.
Given that the event E is that card is not an ace of hearts.
(a) p – 1
(b) p
(c) 1 – p
(d) 1 – 1/p
Q 21) The probability that a non leap year selected at random will contain 53 Sundays is
(a) 1/7
(b) 2/7
(c) 3/7
(d) 5/7
Ans: a
Explanation:
Non-leap year = 365 days
365 days = 52 weeks + 1 day
For 52 weeks, number of Sundays = 52
1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Total possible outcomes = 7
The number of favorable outcomes = 1 Thus, the probability of getting 53 Sundays = 1/7
(a) 1/7
(b) 2/7
(c) 3/7
(d) 5/7
(a) 1/7
(b) 2/7
(c) 4/7
(d) 6/7
Ans: d
Solution Hint
In an ordinary year probability of getting 53 Tuesday is =
In an ordinary year probability of not getting 53 Tuesday is = 1- =
(a) 7
(b) 14
(c) 21
(d) 28
Ans: b
Explanation:
Total number of eggs = 400
(a) 0.62
(b) 0.38
(c) 0.58
(d) 0.42
(a) 0
(b) 1
(c) 1/3
(d)1/2
Ans: d
Explanation: Reason: S = [HH, HT, TH, TT] = 4
a) 1/ 7
b) 2/ 7
c) 3/ 7
d) 4/ 7
Ans: c
No. of vowel = 3 [∵ Vowel are O, I, E]
∴ P(a vowel) = 3/7
a) 1/ 20
b) 1/ 4
c) 1/ 3
d) 1/ 2
(a) 6
(b) 18
(c) 81
(d) 216
Ans: d
a) 2/ 5
b) 3/ 5
c) 4/5
d) 1
a) 1/ 13
b) 4/ 13
c) 12/ 13
d) 3/ 13
(a) 400
(b) 750
(c) 480
(d) 240
Ans: c
Q 33)
A man is known to speak truth 3 out of 4 times. He throws a die and a number other than six comes up. Find the probability that he reports it is a six.
a) 3/ 4
b) 1/ 4
c) 1/ 2
d) 1
Ans: b
Explanation:
Probability of telling a truth = 3/4
Required Probability = 1/ 4
(a) 1.5
(b) 3 / 5
(c) 25%
(d) 0.3
a) 4/ 25
b) 8/ 25
c) 7/ 25
d) 2/ 25
Q 36) An integer is chosen at random from 1 to 100, Find the probability that it is a prime number
a) 4/ 25
b) 8/ 25
c) 1/ 4
d) 2/ 5
Q 37) A jar contains 24 marbles, some are green and some others are blue. If a marble is drawn at random from the jar, the probability that it is green is 2/ 3. Find the number of blue marbles.
a) 12
b) 10
c) 8
d) 16
Q 38) Three coins are tossed together. Find the probability of getting at most 2 tails.
a) 7/ 8
b) 3/ 4
c) 1/ 8
d) 5/ 8
Ans: a
Solution Hint
When 3 coins are tossed then possible outcomes are as follows
{HHH, HHT, HTH, THH, HTT, THT, TTH, TTH}
P(Getting at most 2 tail) = P(≤ two tails) = P(2 tail) + P(1 tail) + P(no tail)
Questions From CBSE Sample Papers (2021-22)
Basic Maths (241)
(a) 1/45
(b) 2/15
c) 4/45
(d) 1/9
(a) 3/5
(b) 1/2
(c) 3/7
(d) 1/3
(a) 0
(b) 1/3
c) 3/4
(d) 1
(a) 0< P(E) ⩽1
(b) 0 < P(E) < 1
c) 0 ≤ P(E) ≤1
(d) 0 ⩽P(E) <1
(a) 1/6
(b) 1/3
c) 1/ 2
(d) 5/6
Standard Maths SP (041)
Q 44) Two fair coins are tossed. What is the probability of getting at the most one head?
(a) 3 ⁄ 4
(b) 1 ⁄ 4
(c) 1 ⁄ 2
(d) 3 / 8
Ans: a
Solution Hint
Possible outcomes are (HH), (HT), (TH), (TT)
Favorable outcomes(at the most one head) are (HT), (TH), (TT) So probability of getting at the most one head =3/4
(a) 4/13
(b) 9/26
(c) 5/13
(d) 11/26
Ans: a
Solution Hint
Number of Possible outcomes are 26
Favorable outcomes are M, A, T, H, E, I, C, S probability = 8/26 = 4/13
(a) 11/13
(b) 12/13
(c) 11/26
(d) 11/52
(a) 5/36
(b) 11/36
(c) 12/36
(d) 23/36
Ans: b
Solution Hint
Outcomes when 5 will come up at least once are-
(1,5), (2,5), (3,5), (4,5), (5,5), (6,5), (5,1), (5,2), (5,3), (5,4) and (5,6) Probability that 5 will come up at least once = 11/36
a) 1/3
b) 0.1
c) 3 %
d) 17/16
a) m – 1
b) m
c) 1 – m
d) 1 + m
a) 2/3
b) 1/ 2
c) 1/6
d) 0
a) I and O
b) M, I, R
c) M, I, O
d) M, I, O, R
a) 1/18
c) 1/36
d) 2/9
Questions from CBSE Final Question Paper 2021-22 (Standard)
a) 1/3
b) 1/4
c) 1/2
d) 1
a) 1/3
b) 1/2
c) 2/3
d) 5/6
a) 1/7
b) 2/7
c) 5/7
d) 6/7
a) 1/5
b) 3/5
c) 2/5
d) 4/5