MCQ | CHAPTER 6 | TRIANGLES
Q 1) Which of the following triangles have the same side lengths?
(a) Scalene
(b) Isosceles
(c) Equilateral
(d) None of these
a) True
b) False
Ans: a
Explanation: Two geometric figures are said to be similar if they are of same shape but different sizes and congruent if they have same shape and size.
a) True
b) False
Ans: a
Explanation The stars in the given figure are congruent because they are same shape and same size. Congruent figures have same shape and size
a) False
b) True
a) AAA test
b) AA test
c) SAS test
d) SSS test
a) True
b) False
Ans: a
Explanation The two figures shown are similar because they have same shape but are different in sizes. The second pentagon is smaller in size as compared to a pentagon, but the basic structure of both the figures is same i.e. both are pentagon.
a) 2.3 cm
b) 5.1 cm
c) 11.74 cm
d) 10.9 cm
(a) 2.5
(b) 3
(c) 5
(d) 6
a) 34 m
b) 28 m
c) 30 m
d) 26 m
(a) 20 cm
(b) 8 cm
(c) 10 cm
(d) 9 cm
Ans: c
Solution Hint
Since diagonals of a rhombus bisects each other at right angle
By Pythagoras theorem,
(16/2)2 + (12/2)2 = side2
a) 30 cm
b) 32 cm
c) 12 cm
d) 16 cm
Ans: b
Solution Hint perimeters of similar triangles is the same as the ratio of their corresponding sides.
a) AAA test
b) AA test
c) SAS test
d) SSS test
a) a = c / b
b) ab = cx
c) bx = ac
d) cb = ax
(a) 230 sq.cm.
(b) 106 sq.cm
(c) 107 sq.cm.
(d) 108 sq.cm
a) 11.23 cm
b) 15.24 cm
c) 14.375 cm
d) 14.275 cm
a) 12 cm
b) 16 cm
c) 18 cm
d) 20 cm
(a) √3/2 a
(b) √3/2 a2
(c) √3/4 a2
(d) √3/4 a
a) 19 : 23
b) 23 : 19
c) 361 : 529
d) 15 : 23
(a) 30 cm
(b) 40 cm
(c) 50 cm
(d) 60 cm
Q 21) In two similar triangles ∆ABC and ∆DEF, AB = 15cm, DE = 5cm. If AL and DM are the altitudes of the triangles ABC, DEF respectively, then what will be the ratio of their altitudes?
b) 1 : 3
c) 1 : 2
d) 2 : 1
a) 4.8 cm
b) 5.6 cm
c) 3.8 cm
d) 5.4 cm
(a) 120°
(b) 60°
(c) 90°
(d) 45°
(a) 22 cm
(b) 20 cm
(c) 21 cm
(d) 18 cm
Ans: d
Solution Hint: ABC ~ DEF
AB = 4 cm, DE = 6 cm, EF = 9 cm and FD = 12 cm
AB/DE = BC/EF = AC/DF
4/6 = BC/9 = AC/12
⇒ BC = (4 x 9)/6 = 6 cm
⇒ AC = (12 x 4)/6 = 8 cm
Perimeter = AB + BC + AC = 4 + 6 + 8 = 18 cm
a) 6 : 7
b) 7 : 6
c) 36 : 49
d) 49 : 36
(a) 4.33 cm
(b) 3.9 cm
(c) 5 cm
(d) 4 cm
a) 8 cm
b) 8.5 cm
c) 7 cm
d) 7.5 cm
a) 4 : 1
b) 1 : 2
c) 2 : 1
d) 1 : 4
(a) ∠A = ∠F
(b) ∠B = ∠D
(c) ∠A = ∠D
(d) ∠B =∠E
a) 2.34 cm
b) 3.45 cm
c) 5√2 cm
d) 2.45 cm
Ans: c
Solution Hint
Radius = 5 cm, Diameter = 10 cm ⇒ AC = 10 cm
Let side of square = x ⇒ AB = BC = x
By Pythagoras theorem
AB2 + BC2 = AC2
b) 40/6
c) 4/3
d) 40/3
(a) 2 : 3
(b) 4 : 9
(c) 81 : 16
(d) 16 : 81
c) 2.4 cm
Ans: a
Solution Hint ratio of areas of similar triangles is equal to the ratio of the squares of their corresponding altitudes.
(a) Circles
(b) Squares
(c) Equilateral triangles
(d) Isosceles triangles
b) 10 / 11
c) 50 / 11
d) 5 / 11
Ans: c
Solution Hint ratio of areas of similar triangles is equal to the ratio of the squares of their corresponding medians.
(a) BD . CD = BC2
(b) AB . AC = BC2
(c) BD . CD = AD2
(d) AB . AC = AD2
a) 19 : 15
b) 225 : 529
c) 529 : 225
d) 15 : 17
Ans: b
Solution Hint Areas of similar triangles is equal to the ratio of the squares of their corresponding angle bisectors.
(a) congruent but not similar
(b) similar but not congruent
(c) neither congruent nor similar
(d) congruent as well as similar
a) 16 : 9
b) 7 : 3
c) 49 : 9
d) 9 : 49
(a) 16
(b) 4
(c) 1/ 4
(d) 1/ 16
Ans: a
Solution Hint
Given, ΔABC ~ ΔPQR
and BC / QR = 1/4
Ratio of area of similar triangles is equal to the square of its corresponding sides. So, ar(ΔPRQ)/ar(ABC) = (QR/BC)2 = (4/1)2 = 16
will be the length of the altitude of an equilateral triangle whose side is 8
cm?
a) cm
b) cm
c) cm
d) cm
Ans: a
cm and DF = 7.5 cm. Then, the following is true:
(a)
DE = 12 cm, ∠F =
50°
(b)
DE = 12 cm, ∠F =
100°
(c)
EF = 12 cm, ∠D =
100°
(d)
EF = 12 cm, ∠D =
30°
Ans:
b
Solution Hint
Given, ΔABC ~ ΔDFE, ∠A =30°, ∠C = 50°, AB = 5 cm, AC = 8 cm and DF= 7.5 cm
In triangle ABC,
∠A + ∠B + ∠C = 180°
∠B = 180° – 30° – 50° = 100°
Since ΔABC ~ ΔDFE, the corresponding angles are equal.
Thus, ∠D = ∠A = 30°
∠F = ∠B = 100°
∠E = ∠C = 50°
And
AB / DF = AC / DE
5 / 7.5 = 8 / DE
DE = (8 × 7.5) / 5 = 12 cm
ratio of areas ∆ABC and trap.(PQCB)?
a) 9 : 7
b) 7 : 9
c) 16 : 7
d) 16 : 9
Ans: c
similarity criterion for two triangles?
(a)
AAA
(b)
SAS
(c)
SSS
(d)
ASA
Ans: d
triangles is equal to
(a)
square of the ratio of their corresponding sides
(b)
cube of the ratio of their corresponding sides
(c) square
root of the ratio of their corresponding sides
(d)
twice the ratio of their corresponding sides
Ans: a
building, if the ladder is 10 m long reaches the top of a building 6 m high
from the ground?
a) 16 m
b) 8 m
c) 12 m
d) 15 m
Ans: b
If the distance between them is 12 m, then what will be the distance between
their tops?
a) 15 m
b) 5 m
c) 23 m
d) 13 m
Ans: d
angled?
a) AB = 3, AC = 8, BC = 6
b) AB = 5, AC = 12, BC = 15
c) AC = 7, AB = 24, BC = 25
d) AC = 7, AB = 24, BC = 26
Ans: c
a) 12 cm
b) 16 cm
c) 12.5 cm
d) 9.6 cm
Ans: d
Solution Hint
First Prove that ΔABC ~ ΔADB, then corresponding sides are proportional
Therefore :
of a rhombus are 15 cm and 36 cm long. Find the perimeter.
a)
96 cm
b)
72 cm
c)
78 cm
d)
84 cm
Ans: c
of two similar triangles are in the ratio 4 : 5. If median of first triangle is
26 cm then find the corresponding median
of the second triangle.
a)
36 cm
b) 28.5 cm
c)
32.5 cm
d) 30 cm
Ans: c
Solution Hint:
When two triangles are
similar then corresponding sides, medians, altitudes, angle bisectors and
perimeters are proportional.
24 cm, then what will be length of the other diagonal?
a) 8.4 cm
b) 4 cm
c) 11 cm
d) 10 cm
Ans: d
Solution Hint
ABCD is a rhombus. The side of the rhombus is
13 cm and the length of one of its diagonal is 24 cm.
Let the length of other diagonal be 2x cm.
Since, diagonals of a rhombus bisect each other
at right angle.
Therefore, AE = x cm
and DE = 12 cm
Now, in ∆AED, by Pythagoras theorem
AD2 = AE2 + DE2
132 = x2 + 122
(Since, AD is the altitude of the triangle it will bisect BC)
x2 = 169 – 144 ⇒ x2 = 25
x = √25 = 5 cm = AE
AC = 2 × AE = 2 × 5 = 10 cm
from the ground. Find the distance of the foot of the ladder from the building.
a) 8 m
b) 12 m
c) 7 m
d) 6 m
Ans: a
What will be the length of the sides of rhombus?
a) 6.40 cm
b) 5.25 cm
c) 2.44 cm
d) 3.29 cm
Ans: a
Solution Hint
Since, diagonals of a rhombus bisect each other at right angles.
Therefore, AE = 4cm and DE = 5 cm
Now, in ∆AED, by Pythagoras Theorem
AD2 = AE2 + DE2
AD2 = 42 + 5 2 (Since, AD is the altitude of
the triangle it will bisect BC)
AD2 = 16 + 25 ⇒ AD2 = 41
AD = √41 cm = 6.40 cm
What will be the shortest route the man could have taken?
a) 13 m
b) 18 m
c) 15 m
d) 10 m
Ans: b
Questions From CBSE Sample Paper 2021-22
Basic Maths SP(241)
the given figure, DE II BC. Which of the following is true?
Ans: c
perimeters of two similar triangles are 26 cm and 39 cm. The ratio of their
areas will be
(a)
2 : 3
(b)
6 : 9
(c)
4 : 6
(d)
4 : 9
Ans: d
vertical stick 20m long casts a shadow 10m long on the ground. At the same time
a tower casts a shadow 50m long. What is the height of the tower?
(a)
30m
(b)
50m
(c)
80m
(d)
100m
Ans: d
an isosceles triangle ABC, if AC = BC and AB2 = 2AC2,
then the measure of angle C will be
(a)
30 ̊
(b)
45 ̊
(c)
60 ̊
(d)
90 ̊
Ans: d
man goes 15m due west and then 8m due north. How far is he from the starting
point?
(a)
7m
(b)
10m
(c)
17m
(d)
23m
Ans: c
is the length of an altitude of an equilateral triangle of side 8cm?
(a)
2√3 cm
(b)
3√3 cm
(c)
4√3 cm
(d)
5√3 cm
Ans: c
∆ABC, B
= 90 ̊ and BD ꓕ AC. If AC = 9cm and AD = 3 cm then BD
is equal to
(a)
2√2 cm
(b)
3√2 cm
(c)
2√3 cm
(d)
3√3 cm
Ans: b
girl walks 200m towards East and then 150m towards North. The distance of the
girl from the starting point is
(a)350m
(b)
250m
(c)
300m
(d)
225
Ans: b
lengths of the diagonals of a rhombus are 24cm and 32cm, then the length of the
altitude
of the rhombus is
(a)
12cm
(b)
12.8cm
(c)
19 cm
(d)
19.2cm
Ans: d
~ ∆PQR. If AM and PN are altitudes of ∆ABC and ∆PQR respectively and AB2
: PQ2 = 4 : 9, then AM : PN =
(a)
16:81
(b)
4:9
(c)
3:2
(d)
2:3
Ans: d
is such that AB = 3 cm, BC = 2cm, CA = 2.5
cm. If ∆ABC ~ ∆DEF and EF = 4cm, then perimeter of ∆DEF is
(a)
7.5 cm
(b)
15 cm
(c)
22.5 cm
(d)
30 cm
Ans: b
the figure, if DE||
BC, AD = 3cm, BD = 4cm and BC = 14 cm, then DE equals
(a)
7cm
(b)
6cm
(c)
4cm
(d)
3cm
Ans: b
the given figure, ∠ACB
= ∠CDA,
AC = 8cm, AD = 3cm, then BD is
(a)
22/3 cm
(b)
26/3 cm
(c)
55/3 cm
(d)
64/3 cm
Ans: c
AB and BE of a right triangle, right angled at B are of lengths 16 cm and 8 cm respectively.
The length of the side of largest square FDGB that can be inscribed in the triangle
ABE is
(a)
32/3cm
(b)
16/3cm
(c)8/3cm
(d)
4/3cm
Ans: b